Kollokvie 010105
Fasit til enkelte av sp?rsm?lene
3)
X^2=(760-750)^2/750+(240-250)^2/250=0.53
d.f.=1
P(0.53,1)=0,47
P-verdi er st?rre enn 0.05. Vi beholder v?r hypotese, 3:1 fordeling.
7b)
F1: Ww Ll x Ww Ll
|
WL |
Wl |
wL |
wl |
WL |
WWLL |
WWLl |
WwLL |
WwLl |
Wl |
WWLl |
WWll |
WwLl |
Wwll |
wL |
WwLL |
WwLl |
wwLL |
wwLl |
wl |
WwLl |
Wwll |
wwLl |
wwll |
8)
b) 1/8 uavhengig av sannsynligheten for ? f? en resessiv homozygot som f?rste barn.
Pp Bb x ppBb
|
PB |
Pb |
pB |
pb |
pB |
PpBB |
PpBb |
ppBB |
ppBb |
pb |
PpBb |
Ppbb |
ppBb |
ppbb |
pB |
PpBB |
PpBb |
ppBB |
ppBb |
pb |
PpBb |
Ppbb |
ppBb |
ppbb |
c)
|
PB |
Pb |
pB |
pb |
pB |
PpBB |
PpBb |
ppBB |
ppBb |
pb |
PpBb |
Ppbb |
ppBb |
ppbb |
pB |
PpBB |
PpBb |
ppBB |
ppBb |
pb |
PpBb |
Ppbb |
ppBb |
ppbb |
Sannsynligheten for begge fenotypene er 3/8.
9)
Dihybrid kryssning; 9:3:3:1
X^2=(223-223.9)^2/223.9+(72-74.6)^2/74.6+(76-74.6)^2/74.6+(27-24.9)^2/24.9
= 0.2976162
d.f.=3
P(0.3,3)= 0,96
Vi godtar dermed hypotesen.
10)
b)
F0: BB HH FFx
Bb Hh Ff
|
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BhF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BHf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
Bhf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
bHF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
bhF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
bHf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
bhf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
8/64=1/8 er
sannsynligheten for ? f? morens genotype.
c)
|
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BHF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BBHHFF |
BhF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BBHhFF |
BHf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
BBHHFf |
Bhf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
BBHhFf |
bHF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
BbHHFF |
bhF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
BbHhFF |
bHf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
BbHHFf |
bhf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
BbHhFf |
8/64=1/8 er sannsynligheten for ? f? farens genotype.
14)
i) F0: Kk x Kk
|
K |
k |
K |
KK |
Kk |
k |
Kk |
kk |
15)
kkMm x Kkmm
|
kM |
km |
kM |
km |
Km |
KkMm |
Kkmm |
KkMm |
Kkmm |
Km |
KkMm |
Kkmm |
KkMm |
Kkmm |
km |
kkMm |
kkmm |
kkMm |
kkmm |
km |
kkMm |
kkmm |
kkMm |
kkmm |
75% d?ve.
16)
Genotype foreldre: Aarr x Aarr -> aarr for mannen
Kryssning med kvinne: AaRr x aarr
|
AR |
Ar |
aR |
ar |
ar |
AaRr |
Aarr |
aaRr |
aarr |
ar |
AaRr |
Aarr |
aaRr |
aarr |
ar |
AaRr |
Aarr |
aaRr |
aarr |
ar |
AaRr |
Aarr |
aaRr |
aarr |
75% har sykdommen.
17)
a)
F0: WWyy x wwYY
F1: WwYy – Alle avkom er hvite
b)
F2: WwYy x WwYy
|
WY |
Wy |
wY |
wy |
WY |
WWYY |
WWYy |
WwYY |
WwYy |
Wy |
WWYy |
WWyy |
WwYy |
Wwyy |
wY |
WwYY |
WwYy |
wwYY |
wwYy |
wy |
WwYy |
Wwyy |
wwYy |
wwyy |
Fenotypisk ratio: 12:3:1
Genotypisk ratio: 1(WWYY):2(WWYy):1(WWyy):2(WwYY):4(WwYy):2(Wwyy):1(wwYY):2(wwYy):1(wwyy)
Dette er et eksempel p? en dihybrid kryssning hvor et av genene er epistatisk til det andre.
c)
P: WwYy x wwYy
|
WY |
Wy |
wY |
wy |
wY |
WwYY |
WwYy |
wwYY |
wwYy |
wy |
WwYy |
Wwyy |
wwYy |
wwyy |
wY |
WwYY |
WwYy |
wwYY |
wwYy |
wy |
WwYy |
Wwyy |
wwYy |
wwyy |
Denne kryssningen gir en ratio: 4:3:1. dette stemmer ikke s? d?rlig med den observerte ratioen 58:39:16
Chi^2= 0.5575221
p-verdi=0,76
18)
P: wwS_ x W_ s _
F1: SsWw x SsWw
Hvit hvit kryssning fra F1.
|
SW |
Sw |
sW |
sw |
SW |
SSWW (h) |
SSWw (h) |
SsWW (h) |
SsWw (h) |
Sw |
SSWw (h) |
SSww(s) |
SsWw (h) |
ssWw (h) |
sW |
SsWW (h) |
SsWw (h) |
ssWW (h) |
ssWw (h) |
sw |
SsWw (h) |
Ssww (s) |
ssWw (h) |
ssww (r) |